![]() We also use watts and kilowatts in solar equations to measure how much electricity the system produces. When we multiply the resulting watts by 1,000, we get kilowatts. Watts are obtained by multiplying voltage and current according to Watt’s Law. When we speak about power, we’re referring to the rate at which appliances consume energy. It is very simple, first enter the amperage to convert, then choose the type of AC or DC current, according to the current chosen different parameters are requested so you must be aware of the boxes on the left in the calculator, then choose the number of phases 1, 2 or 3, this parameter only applies to when you choose AC current, then enter the power factor, if you do not know what power factor the load has you can see some here.Ĭontinue entering the voltage, this section is very important, you must enter the voltage indicated by the table to the left (line-line voltage or line-neutral voltage), otherwise the result may not be correct, finally you give “Calculate” and then if you want to perform another “restart” calculation.A kilowatt is a measure of electrical power equivalent to 1,000 W. Power Factor Requirements for Electronic Loads in California- Brian Fortenbery,2014 Reference // Power Factor in Electrical Energy Management-A. ![]() Typical power factor of common household electronics: Electronics device Typical Un-improved Power Factor by Industry: Industry Typical power factor for engines, constructions and appliances. Note: The conversions of the previous table were made taking into account a power factor of 0.8, a voltage of 220V, with a three-phase AC power, for different variables the calculator that appears at the beginning must be used. Rta: // To know the answer, you must multiply the amperage 30A, by the voltage line to neutral 127V, by the power factor and by 2, and then divide the previous one by 1000, as follows: (30Ax127Vx0,99 × 2) / 1000, resulting in: 7.54kW Amperes to kW, equivalence table, conversion and transformation (Fp = 0.8, voltage = 220V, AC, 3F): How many Amps are: We have a 30A, bifasica stove, with a voltage of 240V line-line and 127 line-neutral, with a power factor of 0.99, which will be the power in kW of the stove? Rta: // Taking into account the formula for monophasic amperage, we must multiply the amperage by the voltage and the power factor, to finally divide the previous one by 1000, as we can see below: (12Ax120Vx0,88) / 1000 = 1, 27kW. We have a hair dryer, single phase, 1F, with an amperage of 12A, a voltage of 120V line-neutral and a power factor of 0.88, what power in kW does the hair dryer have? ![]() Rta: // To find the result we must multiply the amperage, the line-line voltage, the power factor and the root of three in the following way: 50Ax220Vx0,85x√3 = 16194, then we simply divide the previous result by 1000, which will give an amperage of 16.1kW ![]() Is there a mill with a load of 50A, three-phase to 220V line-line, with a power factor of 0.85 and a line-neutral voltage of 127V, which will be the power in kW of the mill? For example, if you have a 220V (Linea-Line) refrigerator with a power factor of 0.8, and a current of 5 Amps, you should multiply 220 × 0.8x√3 × 5 and obtain 1524.20. Multiply the corresponding voltage according to the formula by the power factor, the current and the root of three.
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